Definite Integral with Modulus | sinx + sin2x + sin3x | JEE MAINS 2026 SHIFT 1
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सिद्ध कीजिए : sin3x + sin2x − sinx = 4sinx cos(x/2) cos(3x/2)
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सिद्ध कीजिए : sin3x + sin2x − sinx = 4sinx cos(x/2) cos(3x/2)
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Shivang Gupta on Instagram: "JEE MAIN 2026 ( 21 Jan – Shift 1 ) Q) The value of integral 6 ∫_0^𝜋 |sinx+sin3x+sin2x|dx is #jee2026 #maths JEE Main 2026 (First Attempt) LIVE Paper Discussion 🔥 | Shift 1 - 21st Jan 2026 ⚡ JEE Main 2026 - Paper Solution - 21 January Shift 1 JEE Main 2026 Paper Solution - 21st Jan - Shift 1 Join us on January 21st (Shift 1) for an exclusive walkthrough of the latest JEE Main paper. This is your chance to decode complex problems, learn time-saving hacks, and build a
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